Answer :
Solution
(A). We are given a 1 x 1 x 3 solid.
(B). If it is enlarged by a scale factor of 2, The new dimension will be 2 x 2 x 6
(C). Here we will find the surface Area of the New divided by the surface area of the former
The number (n) needed is
[tex]\begin{gathered} n=\frac{2\left(LB+LH+BH\right)}{2\left(lb+lh+bh\right?} \\ n=\frac{LB+LH+BH}{lb+lh+bh} \\ n=\frac{2\left(2\right)+2\left(6\right)+2\left(6\right)}{1\left(1\right)+1\left(3\right)+1\left(3\right)} \\ n=\frac{4+12+12}{1+3+3} \\ n=\frac{28}{7} \\ n=4 \end{gathered}[/tex]Therefore, four 1 x 1 x 3 solids would be needed
(D).
Scale factor = 3
[tex]Volume=3^3=27[/tex]The volume would be 27 times larger