Answer:
Step-by-step explanation:
Solving a quadratic equation:
ax² + bx + c = 0
The solution is given by:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]In this question:
2x² - 4x - 12 = 0
Dividing everything by x
x² - 2x - 6 = 0
So a = 1, b = -2, c = -6
[tex]x=\frac{-(-2)\pm\sqrt[]{(-2)^2-4\ast1\ast6}}{2}=\frac{4\pm\sqrt[]{28}}{2}=\frac{4\pm\sqrt[]{4\ast7}}{2}=\frac{4\pm2\sqrt[]{7}}{2}[/tex][tex]\frac{4\pm2\sqrt[]{7}}{2}=2\pm\sqrt[]{7}[/tex]