Given:
A(-5,4)
B(3,4)
C(3,-5)
So point D is:
so point D is (-5,-5)
For AB is
Distance between two point is:
[tex]\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}[/tex]so distance between A(-5,4) and B(3,4) is:
[tex]\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}[/tex]So AB is 8 unit apart.
For B(3,4) and C(3,-5).
[tex]\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}[/tex]So BC is 9 unit apart.
For fourth bush point is (-5,-5) it left of point C(3,-5) is:
[tex]\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}[/tex]so fourth bush is 8 unit left of C.
For fourth bush(-5,-5) below to point A(-5,4)
[tex]\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}[/tex]so fourth bush 9 units below of A.
