Explanation
the equation of a circle is given by:
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{where} \\ (h,k)\text{ is the center} \\ \text{and r is the radius} \end{gathered}[/tex]so
[tex]\begin{gathered} (x+9)^2+(y+5)^2=64 \\ +9=-h \\ so,\text{ h=-9} \\ and \\ 5=-k \\ k=-5 \end{gathered}[/tex]so, the center is
[tex](-9,-5)[/tex]Step 2
now, the radius
[tex]\begin{gathered} (x+9)^2+(y+5)^2=64 \\ so \\ 64=r^2 \\ \text{square root in both sides} \\ \sqrt[]{64}=\sqrt[\square]{r^2} \\ 8=r \\ \text{hence, the radisu is 8} \\ r=8 \end{gathered}[/tex]I hope this helps you