Answer :
The amount of charge that drifts through the cross section in 3.80ms is 1.064* 10-13 C.
voltage (V) = 3.40nV = 3.4*10-9 V
length (l) = 2.00cm = 0.2m
radius (r) = 2 mm = 0.002m
time (t) = 3.08 ms = 3.8*10-3 sec
resistivity of copper wire (ρ) = 1.62 * 108 Ωm
Area of cross section (A) = 2πr2
A = 2 * 3.14 * 4 * 10,00,000
resistance (R) = ρ*l/A
= (1.62 * 108 * 0.2)/( 2 * 3.14 * 4 * 10,00,000)
R = 1.2 Ω
Ohm’s law gives the relationship between electric current and potential difference. The current that flows through conductors is directly proportional to the voltage applied to it.
Or mathematically it can be written as
I ∝ v
or
V = I R
I = V/R
I = (3.4 × 10⁻⁹) / 1.2
I = 2.8 nA
I = Q/t
Q = I×t
= (2.8 ×10⁻⁹) × (3.8 × 10⁻³)
= 1.064× 10⁻¹³ C
find more on charge and potential difference :
brainly.com/question/4724150
#SPJ4
