KhennediF433347 KhennediF433347

25-10-2022
Chemistry

Answered

What is the specific heat capacity of a substance if it takes 4.4 kJ of heat to warm511.2 g by 16.3°C?

Answer :

AydinT105137 AydinT105137

25-10-2022

Explanation

The equation that relates a temperature change and the heat required is:

[tex]Q=mc\Delta T[/tex]

Where Q is the head requiredm m is the mass involved, cis the specific heat capacity and ΔT is the change in temperature.

Since we are warming, the change in temperature is positive, so:

[tex]\Delta T=16.3\degree C[/tex]

And we also have Q and m:

[tex]\begin{gathered} Q=4.4kJ=4400J \\ m=511.2g \end{gathered}[/tex]

Solving the equation for c and inputting the values, we have:

[tex]\begin{gathered} Q=mc\Delta T \\ c=\frac{Q}{m\Delta T}=\frac{4400J}{511.2g16.3\degree C}=0.5280\ldots J/(g\degree C)\approx0.53J/(g\degree C) \end{gathered}[/tex]

Answer

The specific heat capacity is approximately 0.53 J/(g°C)

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