a long, thin solenoid has 700 turns per meter and radius 2.50 cm. the current in the solenoid is increasing at a uniform rate of 48.0 a/s. part a what is the magnitude of the induced electric field at a point near the center of the solenoid? express your answer with the appropriate units. e



Answer :

The magnitude of the induced electric field at a point near the center of the solenoid is E =0 v/m at a point 0.500 cm from the axis of the solenoid is E = 1.05 × 10^-7 v/m.

formula for magnetic field due to solenoid is ,

B=μ₀nI

E=μ₀nI/2 dI/dt

E = 4π×10^-7 × 700 ×0×48/2

E=0v/m at center of the solenoid.

at r= 0.5cm

E=4π×10^-7 × 700 ×0.5×10^-2×48/2

E=1.05×10^-4 v/m

A long, thin wire loop that is frequently wrapped around a metallic core is referred to as a solenoid in physics. When an electric current is sent through it, the solenoid creates a magnetic field. Solenoids play a crucial role since they can generate precise magnetic fields and function as electromagnets. Its magnetic field has a form that is highly reminiscent to a bar magnet's field when a direct electric current is conducted through it. In a solenoid, the field is powerful and constant. A greater overall magnetic field is created as a result of the little magnetic fields that are produced by the current in each turn of the coil.

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