The minimum sample size of the given condition is 89.
In given condition,
For 95% confidence level, critical value of z is z* = 1.96
The margin of error given is E = 1
Standard deviation ( α ) = 4.8
Final required sample size is;
n = [tex](\frac{z*\alpha }{E} )^{2}[/tex]
= [tex](\frac{1.96 * 4.8}{1} )^2[/tex]
= 88.51
n ≅ 89
The minimum sample size of the given condition is 89.
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