a light string is wrapped around the edge of the smaller disk, and a 1.50 kg block is suspended from the free end of the string. if the block is released from rest at a distance of 2.00 m above the floor, what is its speed just before it strikes the floor?



Answer :

According to the given statement 6.26 m /s  is its speed just before it strikes the floor.

What is Kinetic energy?

An item in motion has energy, which is called kinetic energy. Motion in space, you walking down the street, and the rotation of the planet around the sun are all examples of kinetic energy. The relationship between kinetic energy and an object's mass and square of its velocity is direct: K.E. = 1/2 mv²

Briefing:

Prior to release, the block's height was 2.00 m, and its mass was 1.50 kg.

potential energy of the block = m g h

= 1.5 x 9.8 x 2.00

= 29.4 J

If v be its velocity before striking the floor

Kinetic energy = 1/2 m v²

Applying conservation of mechanical energy

Kinetic energy = potential energy

1/2 m v² = 29.4

.5 x 1.5 x v² = 29.4

v² = 39.2

v = 6.26 m /s

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