Based on the mean miles between the services and the standard deviation, the probability that the mean of 32 cars as a sample would be less than 4,424 miles is 0.0027.
The required probability is for the possibility that in a sample of 32 cars, the number of services would be less than 4,424.
The probability can be found by the formula:
P (x < 4,424) = P ( Z < (4,424 - 4,639) / (437 / √32))
This gives us:
P (x < 4,424) = P ( Z < -2.78)
Using the Z table shows that the probability would be 0.0027.
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