an empty spherical weather balloon with a mass of 5.00 kg has a radius of 2.879 m when fully inflated with helium. it is to carry a small load of instruments with a mass of 10.0 kg. taking the density of air to 1.16 kg/m^3 and the density of helium to be 0.160 kg/m^3, will the balloon get off the ground?



Answer :

Buoyant force > Net Weight. So it will get off the ground.

What is Density?

Density is defined as the measurement of mass per unit volume. It is represented by the formula

D = m/v

Where,

D = Density

m = Mass

v = Volume

Now by putting the value in the above formula we get the mass as

Helium Mass = Density × Volume

= 0.160 kg/m³ × 4/3 × pi × r³ m³

= 15.99 kg

Total Mass of Ballon = Mass of Instruments + Mass of Helium Filled + Empty Mass of Ballon

Total Mass of Ballon = 10.0 + 15.99 + 5.00

Total Mass of Ballon = 30.99 Kg

Displaced air mass = Density × Volume

Displaced air mass = 1.16 kg/m³ × 4/3 × pi × r³ m³

Displaced air mass = 115.89 Kg

Now,

Buoyant Force = Mass × 9.8

= 115.89 Kg × 9.8

Net Force = Mass × 9.8

= 30.99 kg × 9.8

Thus from the above conclusion we can say that the Buoyant force > Net Weight. So it will get off the ground.

Learn more about the Density here: https://brainly.com/question/1354972

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