a heavy seesaw is out of balance. a lightweight girl sits on the end that is tilted downward, and a heavy boy sits on the other side so that the seesaw now balances. if the boy and girl both move forward so that they are one-half their original distance from the pivot point, what will happen to the seesaw?



Answer :

The side the girl is sitting on will once tilt down.

The seesaw's left and right sides' opposing torques are balanced by the torque acting on the left side. The force will act on the seesaw itself at either the right or left side of the seesaw's center of gravity.

Formula: The expression for the amount of torque operating on a body is

torque =r F

where; r=position vector and F= force

if the force is applied at a right angle to the direction of r and the body is at a distance r from the pivot.

The seesaw's length is assumed to be l, and its left side's mass is assumed to be greater than its right side's mass.

[tex]m_{L}[/tex] > [tex]m_{R}[/tex]

Let the weight of the hefty body be [tex]M[/tex], and the mass of the girl be [tex]m[/tex].

The seesaw's left and right side rods' centers of gravity will be positioned [tex]\frac{l}{4}[/tex] of an inch apart from the center (or pivot). The girl and body are initially positioned [tex]\frac{l}{2}[/tex] apart from the pivot. as a result, initially

torque of left side= torque of right side

([tex]\frac{l}{4}[/tex])[tex]m_{L}[/tex][tex]g[/tex]+([tex]\frac{l}{2}[/tex])[tex]mg[/tex]=([tex]\frac{l}{4}[/tex])[tex]m_{R}[/tex][tex]g[/tex]+([tex]\frac{l}{2}[/tex])[tex]Mg[/tex]

we get,

[tex]\frac{m_{L} -m_{R} }{2}[/tex]= [tex]M-m[/tex]

Asking the body and the girl to move ([tex]\frac{l}{4}[/tex]) closer to the pivot will result in the following calculation of the net torque:

net torque= torque of left - torque of right

The seesaw is tilted to the left when we believe that the torque is greater on the left side.

τnet=[tex]\frac{l}{4} m_{L}[/tex][tex]g[/tex]+[tex]\frac{l}{4}[/tex][tex]mg[/tex]−[tex]\frac{l}{4} m_{R}[/tex][tex]g[/tex]−[tex]\frac{l}{4}[/tex][tex]Mg[/tex]

We obtain the following values by replacing the value of [tex]m_{L} -m_{R}[/tex] in terms of [tex]m[/tex] and [tex]M[/tex]

therefore,

 τnet=[tex]lg(\frac{M-m}{4} )[/tex]

Our presumption that the left side will tilt because M is heavy and m is tiny is valid since the torque on the left side will predominate.

The girl will again be sitting on the side that is tilting downward because she was previously sat on the left.

REMARK: We would have discovered negative net talk if we had thought that the right hand side was tilting or had more torque. As a result, in such scenario, we would have discovered that the left side tilts, contrary to what we had assumed. Both strategies are thus appropriate. But it is important to avoid guessing at all costs while answering these questions because doing so reduces the likelihood of getting the correct response.

what is torque?

The force that can cause an object to rotate along an axis is measured as torque. An object acquires angular acceleration due to torque.

learn more about torque

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