a 30.0 kg child starting from rest slides down a water slide with a vertical height of 10.0m. what is the child's speed (a) halfway down the slides vertical distance and (b) three-fourths of the way down?



Answer :

a)Child's speed halfway down the slide is 9.89m/s.

b)Child's speed three fourth of the way down is 12.12 m/s.

Potential energy that a massive object has in relation to another massive object due to gravity is called gravitational potential energy. Potential energy associated with the gravitational field is converted to kinetic energy when the objects falls towards each other.

As we know that, ΔPE=KE

mgΔh=mv²/2

Now, v=sqrt(2gΔh)

Halfway down the slide,  Δh=5 m

gravity = 9.8 m/s²

v=sqrt(2gΔh)

v= √2* 9.8 * 5

=  √98

= 9.89 m/s

For the three fourth of the way down, Δh=7.5 m.

v= √2* 9.8 * 7.5

= 12.12 m/s

To know more about gravitational potential energy, refer

https://brainly.com/question/3120930

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