The probability that the sample mean would be greater than 148.6 millimeters is 0.017
The spread of all the data points in a data collection is taken into account by the variance, which is a measure of dispersion.
Given Population mean μ= 147
Population Variance σ^2 = 25
So, population SD = 5
Size of sample = n = 44 Sample mean = x
To find P( y > 148.6) :
SE =σ/√n =
5/√44= 0.7538
Transforming to Standard Normal Variate:
Z = (x - μ )/SE
= (148.6 - 147)/0.7538
= 2.1226
From Table of Area Under Standard Normal Curve, corresponding to Z = 2.1226, area = 0.4830.
So, required probability = 0.5 - 0.4830 = 0.017
The probability that sample mean would be greater than 148.6 millimeters is 0.017
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