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Find the equation of the line perpendicular to y=2x-6 that passes through (4,5)



Answer :

hbj

Answer:

y = -1/2x + 7

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = 2x - 6. Its slope is 2. A line perpendicular to this one will have a slope of -1/2.

Plug this value (-1/2) into your standard point-slope equation of y = mx + b.

y = -1/2x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (4, 5). Plug in the x and y values into the x and y of the standard equation.

5 = -1/2(4) + b

To find b, multiply the slope and the input of x (4)

5 = -2 + b

Now, add 2 to both sides to isolate b.

7 = b

Plug this into your standard equation.

y = -1/2x + 7

This equation is perpendicular to your given equation (y = 2x - 6) and contains point (4, 5).

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View image hbj

Answer: y = -1/2x + 7

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = 2x - 6. Its slope is 2. A line perpendicular to this one will have a slope of -1/2.

Plug this value (-1/2) into your standard point-slope equation of y = mx + b.

y = -1/2x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (4, 5). Plug in the x and y values into the x and y of the standard equation.

5 = -1/2(4) + b

To find b, multiply the slope and the input of x (4)

5 = -2 + b

Now, add 2 to both sides to isolate b.

7 = b

Plug this into your standard equation.

y = -1/2x + 7

This equation is perpendicular to your given equation (y = 2x - 6) and contains point (4, 5).