Answer :
A 50. 0-g sample of water at 80°C is added to a 50. 0-g sample of water at 20°C. The final temperature of the water should be 50 °C.
mass of water, m1 = 50 g
temperature, T1 = 80°C
mass of water, m2 = 50 g
temperature, T2 = 20°C
Final temperature = ?
C = 1
Formula
mCΔT = - mCΔT
Substitution
50(Te - 80) = - 50(Te - 20)
50 Te - 4000 = - 50 Te + 1000
50Te + 50Te = 1000 + 4000
100Te = 5000
Te = 5000 / 100
Te = 50 °C
The final temperature of the water should be 50 °C.
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