how many students (find n-sample size) must be randomly selected to estimate the mean weekly earnings of students at one college? we want 95% confidence that the sample mean is within $2 of the population mean, and the population standard deviation is known to be $53.



Answer :

The sample size needed to calculate the average weekly salary for students at one college is 2698.

The term population mean, which is the average score of the population on a given variable, is represented by: μ = ( Σ Xi ) / N. The symbol 'μ' represents the population mean.

The (1 - α)% confidence interval for population mean (μ) is:

[tex]CI = x[/tex] ± [tex]\frac{z_{a} }{2}[/tex] * σ/[tex]\sqrt{n}[/tex]

The margin of error of a (1 - α)% confidence interval for population mean (μ) is:

[tex]MOE = \frac{z_{a} }{2}[/tex] * σ/[tex]\sqrt{n}[/tex]

The information provided is:

σ = $53

MOE = $2

The critical value of z for 95% confidence level is:

[tex]z_{\frac{a}{2} }[/tex] = [tex]z_{\frac{0.05}{2} }[/tex]

= [tex]z_{0.025}[/tex]

= 1.96

Compute the sample size as follows:

[tex]MOE = \frac{z_{a} }{2}[/tex] * σ/[tex]\sqrt{n}[/tex]

n = [([tex]z_{\frac{a}{2} }[/tex] *  σ)/MOE]2

n = [tex](\frac{1.96*53}{2} )^{2}[/tex]

n = 2697.76

n ≅ 2698

Therefore,

The sample size needed to calculate the average weekly salary for students at one college is 2698.

To learn more about information visit Population mean :

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