The height of an "angry bird" shot into the sky as a function of time (seconds) is h = 8.65 ft.
The height of the bird is given by the following equation
h(t)= -0.25t2 + 1.9t + 17
t= 1
= -0.25 + 1.9 + 17
= -8.35 + 17
h = 8.65 ft.
The following are the three equations:
-First equation of motion: v = u + at
-Second equation of motion: s = u t + 1/2 at2
Third equation of motion: v2 = u2 + 2as
t is the time, in seconds.
h(t) is the height, in feet, which is dependent of the time.
h(t) is height in feet and t is time in seconds
then h = 8.65 ft.
To learn more about Motion Equation visit:
brainly.com/question/15080570
#SPJ4