a publisher reports that 55% of their readers own a particular make of car. a marketing executive wants to test the claim that the percentage is actually below the reported percentage. a random sample of 100 found that 49% of the readers owned a particular make of car. is there sufficient evidence at the 0.10 level to support the executive's claim?



Answer :

The proportions are variable, according to statistics. By null hypothesis, [tex]H_{0}[/tex] has been approved.

The null hypothesis asserts that the two options are identical. The null hypothesis states that the differences observed are solely attributable to chance. The alternative hypothesis, on the other hand, is a statement employed in statistical inference studies. It is opposed to the null hypothesis and therefore is symbolized by [tex]H_{0}[/tex] or [tex]H_{1}[/tex].

Using p-value, the sample data, test type, and sampling pattern of the statistical test under the null hypothesis are used to determine the p-value.

[tex]H_{0}[/tex]: p is not 55% vs [tex]H_{1}[/tex]: p = 55%

The standard deviation is,

σ = √(P × (( 1 - P ) ÷ n) = √(0.55 × (0.33 ÷ 100)) = 0.0426

z - score is (p - P) ÷ σ = (0.55 - 0.49) ÷ 0.0426 = 1.408

Read more about the null hypothesis at

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