(1) Number of students who play both table tennis and cricket ball is 5
(2) number of students play cricket ball only is 8.
Let, 'A' be the set of students who play cricket,
Let, 'B' be the set of students who play tennis.
It is given that,
Number of students who play cricket = n(A) = 13
Number of students who play tennis = n(B) = 12
Total Number of students in a class = n(A∪B) = 20
n(A∩B)= Number of students who play both the games.
(1) Number of students who play both the games can be calculated using the following formula;
n(A∪B) = n(A) + n(B) - n(A∩B)
20 = 13 + 12 - n(A∩B)
n(A∩B) = 13 + 12 - 20 = 5
5 students who play both the games.
(2) Number of students that play cricket ball only = n(A) - 5 = 13 -5 = 8
So, 8 number of students play cricket ball only.
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