We are given the function
[tex]y=7^x[/tex]
To complete the missing values of the table, we simply replace the value of x for each empty space of the table.
IN this case, we are missing the value of y when x=2. So, we calculate it as follows
[tex]y=7^2=49[/tex]
So the value of y when x=2 is 49.
Now we calculate it for x=0. We get
[tex]y=7^0=1[/tex]
THen the value of y when x=0 is 1.
Finally we want to check the value of y when x=-2. We have that
[tex]y=7^{\text{ -2}}^{}^{}[/tex]
Recall that given a non zero number a and a number b, we have that
[tex]a^{\text{ -b}}=\frac{1}{a^b}[/tex]
IN this case we have a=7 and b=2, so we ge t
[tex]y=7^{\text{ -2}}=\frac{1}{7^2}=\frac{1}{49}[/tex]
This means that the missing value, when x=-2, is 49
