When a red light with a wavelength of 670 nm shines on a piece of metal, an electron is ejected. What is the energy of the photon absorbed by the electron to overcome the attractive forces?.

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25-10-2022
Physics

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When a red light with a wavelength of 670 nm shines on a piece of metal, an electron is ejected. What is the energy of the photon absorbed by the electron to overcome the attractive forces?.

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contexto1026 contexto1026 · Answer 1 · 2022-11-04T05:47:38-04:00

The electricity (i.e., energy) of the photon of mild as we are able to see right here 2.9 * [tex]10^{-19}[/tex] J.

We recognize that mild has to do with any of the additives of the electromagnetic spectrum. These are the sorts of radiation which might be capable of byskip thru vacuum due to the fact they do now no longer want a medium for the propagation of the wave. We at the moment are requested to achieve the electricity of the photon primarily based totally withinside the wavelength that we had been provided withinside the query right here.

We have that the wavelength of the photon from what we are able to see withinside the query had been given as 670 nm. then

E = h*c / λ

E = energy of the light

h = Plank's constant

c = speed of light

λ = wavelength of the light

It then follows that;

E = 6.6 * [tex]10^{-34}[/tex] * 3 * [tex]10^{8}[/tex]/670 * [tex]10^{9}[/tex]

E = 2.9 * [tex]10^{-19}[/tex]J

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