We know that
• The volume of one ball is 221 cubic centimeters.
Since the ball is spherical, we can find its radius with the following formula.
[tex]\begin{gathered} V=\frac{4}{3}\pi r^3 \\ 221\cdot\frac{3}{4\pi}=r^3 \\ r^3=\frac{663}{4\pi} \\ r=\sqrt[3]{\frac{663}{4\pi}}\approx3.75 \end{gathered}[/tex]
The diameter would be double than the radius, by definition.
[tex]d=2(3.75)=7.5[/tex]
Since there are three balls in the cylinder, the height would be
[tex]h=3(7.5)=22.5[/tex]
Now, we find the volume of the cylindrical package.
[tex]V=\pi r^2h=\pi(3.75)^2(22.5)\approx993.52[/tex]
Therefore, the volume of the cylindrical package is 993.52, approximately.
