The mean amount of time it takes a kidney stone to pass is 16 days and the standard deviation is 5 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(16Correct,5Correct) b. Find the probability that a randomly selected person with a kidney stone will take longer than 17 days to pass it. 0.2Incorrectc. Find the minimum number for the upper quarter of the time to pass a kidney stone. 0.8Incorrect days.



Answer :

Answer:

• (a)X ~ N(16, 5)

,

• (b)0.4207

,

• (c)19.37 days

Explanation:

(a)

• The mean amount of time = 16 days

,

• The standard deviation = 5 days.

Therefore, the distribution of X is:

[tex]X\sim N(16,5)[/tex]

(b)P(X>17)

To find the required probabability, recall the z-score formula:

[tex]z=\frac{X-\mu}{\sigma}[/tex]

When X=17

[tex]z=\frac{17-16}{5}=\frac{1}{5}=0.2[/tex]

Next, find the probability, P(x>0.2) from the z-score table:

[tex]P(x>0.2)=0.4207[/tex]

The probability that a randomly selected person with a kidney stone will take longer than 17 days to pass it is 0.4207.

(c)The upper quarter is the value under which 75% of data points are found.

The z-score associated with the 75th percentile = 0.674.

We want to find the value of X when z=0.674.

[tex]\begin{gathered} z=\frac{X-\mu}{\sigma} \\ 0.674=\frac{X-16}{5} \\ \text{ Cross multiply} \\ X-16=5\times0.674 \\ X=16+(5\times0.674) \\ X=19.37 \end{gathered}[/tex]

The minimum number for the upper quarter of the time to pass a kidney stone is 19.37 days.