Answer:
Explanation:
Given the expression:
[tex]\sqrt{12(x-1)}\div\sqrt{2(x-1)^{2}}[/tex]
By the division law of surds:
[tex]\sqrt[]{x}\div\sqrt[]{y}=\sqrt[]{\frac{x}{y}}[/tex]
Therefore:
[tex]\sqrt[]{12(x-1)}\div\sqrt[]{2(x-1)^2}=\sqrt[]{\frac{12(x-1)}{2(x-1)^2}}[/tex]
The result obtained can be rewritten in the form below:
[tex]=\sqrt[]{\frac{2\times6(x-1)}{2(x-1)(x-1)^{}}}[/tex]
Canceling out the common factors, we have:
[tex]=\sqrt[]{\frac{6}{(x-1)^{}}}[/tex]
An equivalent expression is Opt
