Given: A circle has a center point at the coordinates P(3,0) with a diameter line RT where R has the coordinates (-47,25).
Required: To determine the coordinates of T.
Explanation: The given circle is-
Let the coordinates of T be (x,y). Then the center of a circle is divided by the diameter in the ratio of 1:1. The section formula for a point (x,y) dividing a line segment in the ratio of 1:1 is-
[tex]\begin{gathered} x=\frac{(x_1+x_2)}{2}, \\ y=\frac{(y_1+y_2)}{2} \end{gathered}[/tex]Hence, for the given line RT, point P divided RT in 1:1. Thus-
[tex]\begin{gathered} 3=\frac{-47+x}{2}, \\ 0=\frac{25+y}{2} \end{gathered}[/tex]Further solving for x and y as-
[tex]\begin{gathered} x=6+47 \\ \Rightarrow x=53 \\ and\text{ }y=-25 \end{gathered}[/tex]Final Answer: The coordinates of T are (53,-25).
