find the rate of change of the volume of a cylinder when its radius is 6 feet if its height is always (3/2) times its radius and its radius is increasing at the rate of 2 feet per minute.



Answer :

ayune

When the radius of a cylinder is 6 ft. and it is increasing at the rate of 2 feet per minute, its volume will change at rate of 509.14 ft³/minute.

Given a cylinder with:

r = radius

h = height = 3/2 . r

The volume of the cylinder is:

V = πr².h

Substitute h = 3/2 . r,

V = πr².(3/2 r)

V = 3/2 . πr³

Take the derivative with respect to t:

dV/dt = 9/2 . πr²  . dr/dt

Substitute dr/dt = 2 ft./minute and r = 6 ft.,

dV/dt = 9/2 . π.6²  

dV/dt = 9/2 . π.6²  = 509.14 ft³/minute.

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