The probability that at least one wheel lands on a multiple of 4 or the first value is strictly greater than 8 is 53/99
The greatest number that can be formed by the two wheels is 99
Let event A be multiple of 4
Multiples of 4 between 1 to 9 is 4,8
Probability that at least one wheel land at a multiple of 4 is
[tex]\frac{2}{9} + \frac{2}{9}[/tex] = 4/9
Let event B be first value greater than 9
P(B) = 9/99 = 1/11
P(A∩B) = 0
Probability of at least one wheel lands on a multiple of 4 or the first value is strictly greater than 8
P(A∪B) = P(A) + P(B) - P(A∩B)
= 4/9 + 1/11 - 0
= [tex]\frac{4(11)}{9 (11)} + \frac{1 (9)}{11(9)}\\\\ \frac{44 + 9}{99}\\\\ \frac{53}{99}[/tex]
Therefore, the probability that at least one wheel lands on a multiple of 4 or the first value is strictly greater than 8 is 53/99
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