two cyclists, 42 miles apart, start riding toward each other at the same time. one cycles 2 times as fast as the other. if they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?



Answer :

The speed of the faster cyclist is 14\ miles/hr.

What is speed?

It is the average distance coverd in unit time. It is also defined as the rate of change of distance with respect to time.

Since the speed of the first cyclist is double than the second cyclist hence, the first cyclist will cover the double distance than the second cyclist. Consider the first cyclist covers 2s distance and first cyclist covers s distance. The sum of these two distances should be 42 miles. Hence,

[tex]2s+s=42\\3s=42\\s=14[/tex]

Now, distance coverd by the first cyclist is [tex]2s=2\times 14\\=28 \ $miles[/tex].

Now, both the cyclists meet after 2 hr hence, time taken by the first cyclist is 2 hr.

[tex]Speed=\frac{Total\ distance}{Total\ time}\\=28\ miles/2 \ hr\\=14\ miles/hr[/tex]

Hence, the speed of the faster cyclist is 14\ miles/hr.

Learn more about speed from the following link:

https://brainly.com/question/13943409

#SPJ4