a cart with a mass of 2.0 kg is pulled across a level desk by a horizontal foirce of 4.0n. if the coeffiecient of kinetic friciton is 0.12 what is the acceleration of the cart



Answer :

Answer:

The acceleration of the cart:

a =  0.82 m/s²

Explanation:

 Given:

m = 2.0 kg

F = 4.0 N

μ = 0.12

g = 9.8 m/s²

___________

a - ?

Friction force:

Ff = μ·m·g

2 Newton's law:

m·a = F - Ff

The acceleration of the cart:

a = ( F - Ff) /m

a =  F/m - (μ·m·g) / m

a =  F/m - μ·g

a = 4.0 / 2.0 - 0.12·9.8 ≈ 0.82  m/s²

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