The two stones will fall at the different time. But the difference between the time is just of one second.
The distance of the cliff is also considered. Here, the speed or velocity is asked. To calculate this we have to use the equation of motion.
There are three equations of motion.
We have;
The kinematic equation of motion that can be used is s = ut - (1/2)·gt²
For the first stone, we have, s₁ = ut₁ - (1/2)·gt₁²
For the second stone, we get; s₂ = ut₂ - (1/2)·gt₂²
g = The acceleration due to gravity ≈ 9.81 m/s²
s = The distance below the cliff top
The initial velocity of the stones, u = 0
To calculate the change of distance between the two stones,
we will subtract the two equation of motions are
s₁-s₂
With all the values kept together in the equation of motion, we can easily find the change of distance between the two stones.
To know more about the motion, refer : https://brainly.com/question/14355103
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