If a simple pendulum has a period t on the earth. if it were used on planet x, where the acceleration due to gravity is 3 times what it is on earth, the time period is 0.577 times the time period on earth.
It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.
As given in the problem a simple pendulum has a period t on the earth. if it were used on planet x, where the acceleration due to gravity is 3 times what it is on earth,
Time period of simple pendulum = 2π √( l / g)
= 2π √( l / 3g)
Thus, the time period is 0.577 times the time period on earth.
To learn more about frequency here, refer to the link given below ;
brainly.com/question/14316711
#SPJ1