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a single-turn circular loop of radius 5.5 cm is to produce a field at its center that will just cancel the earth's field of magnitude 0.7 g directed at 70 below the horizontal north direction. find the current in the loop.



Answer :

The current in the loop will be 6.13 A.

What is a magnetic field ?

The magnetic field is the area in and around a magnet that is subject to the effects of magnetism. We employ the magnetic field as a tool to describe the distribution of the magnetic force in the vicinity and inside something magnetic in nature.

According to the question,

Radius of loop,

r =5.5 cm or,

r  = 0.055 m                          

Earth's magnetic field,  = 0.7G = 0.7 × 10⁻⁴ T

Number of turns, N = 1

We know the relation,

B = µ₀ ×N×I/2r

B = [tex]B_{e\\}[/tex]

then,

[tex]B_{e\\}[/tex] = µ₀ ×N×I/2r

By substituting the values,

0.7 × 10⁻⁴ = 4π × 10⁻⁷×1 × I / 2× 0.055

hence,

The current will be

I = 2× 0.055 × 0.7 × 10⁻⁴/ 4π ×10⁻⁷×1

I = 6.13A

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