Notice that " PO4 " appears in two different places in this chemical equation. PO 3−4 is a polyatomic ion called phosphate . What number should be placed in front of Na3PO4 to give the same total number of phosphate ions on each side of the equation?
?Na3PO4+MgCl2→Mg3(PO4)2+NaCl

Express your answer numerically as an integer.



Answer :

PO₄ appears in two different places in this chemical equation. PO₃⁻⁴ is a polyatomic ion called phosphate. 2 should be placed in front of Na₃PO₄ to give the same total number of phosphate ions on each side of the equation.

For the reaction -

? Na₃PO₄ + MgCl₂  →  Mg₃(PO₄)₂ + NaCl

There are 2 phosphate ions present on the product side, therefore, 2 phosphate atoms should be present on the reactant side to maintain the equilibrium.

On product side, number of ions of magnesium is 3, so to attain the equilibrium and balance the equation there 3 ions of magnesium should be on the reactant side.

In order to balance the number of ions of phosphate and magnesium in the reaction which is given -

On the reactant side, 6 atoms of chlorine and sodium are formed, in order to balance these 6 atoms of chlorine and sodium, 6 atoms of each should be present on the product side.

Therefore, the balanced chemical equation is -

2 Na₃PO₄ + 3 MgCl₂  →  Mg₃(PO₄)₂ + 6 NaCl

To learn more about chemical equation,

brainly.com/question/12946825

#SPJ1