The mass in grams of 2.73×1024 molecules of methanol is 154.20g.
given that:
no. of molecules = 2.73 × 10²⁴
molar mass of methanol (CH₄O) = 34.04 g/mol
moles of methanol = no. of molecules / Na
= 2.73 × 10²⁴ / 6.022× 10²³
= 4.53 mol
now, formula for the no. of mole is given as :
no. of moles = mass / molar mass
mass = no. of mole × molar mass
mass = 4.53 ×34.04
mass = 154.20 g
Thus, the mass in grams of 2.73 × 10²⁴ molecules of methanol is 154.20 g
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