The number of each type of coins are as follows:
q = 15 quarters.
d = 30 dimes.
n = 25 nickels.
In order to solve this word problem, we would assign a variables to the unknown numbers and then translate the word problem into algebraic equation as follows:
Let d represent the number of dimes.
Let q represent number of quarters.
Let n represent number of nickels.
Let T represent total number of coins.
Note: 1 quarter is equal to 0.25 dollar, 1 nickel is equal to 0.5 dollar, and 1 dime is equal to 0.1 dollar.
Translating the word problem into an algebraic equation, we have;
Dimes; d = 2q .....equation 1.
Nickels; (70 - (q + 2q)) = (70 - 3q) .....equation 2.
Total coins; T = n + d + q
0.5(70 - 3q) + 2q(0.1) + q(0.25) = 8.00
Multiplying all through by 100, we have:
5(70 - 3q) + 2q(10) + q(25) = 800
350 - 15q + 20q + 25q = 800
350 + 30q = 800
30q = 800 - 350
30q = 450
q = 450/30
q = 15 quarters.
For the number of dimes, we have:
Dimes, d = 2q
Dimes, d = 2(15)
Dimes, d = 30 dimes.
For the number of nickels, we have:
Nickels, n = (70 - 3q)
Nickels, n = (70 - 3(15))
Nickels, n = (70 - 45)
Nickels, n = 25 nickels.
Read more on equations here: https://brainly.com/question/1511173
#SPJ1