In the given figure ABC is a triangle inscribed in a circle with center O. E is the midpoint of arc BC . The diameter ED is drawn . Prove that ​

In the given figure ABC is a triangle inscribed in a circle with center O E is the midpoint of arc BC The diameter ED is drawn Prove that class=


Answer :

Answer:

  we can use two ways to write 180° along with the inscribed angle theorem to obtain the desired relation

Step-by-step explanation:

Given ∆ABC inscribed in a circle O where E is the midpoint of arc BC and ED is a diameter, you want to prove ∠DEA = 1/2(∠B -∠C).

Setup

We can add add arcs to make 180° in two different ways, then equate the sums.

  arc EB +arc BA +arc AD = 180°

  arc EC +arc CA -arc AD = 180°

Equating these expressions for 180°, we have ...

  arc EB +arc BA +arc AD = arc EC +arc CA -arc AD

Solution

Recognizing that arc EB = arc EC, we can subtract (arc EB +arc BA -arc AD) from both sides to get ...

  2·arc AD = arc CA -arc BA

The inscribed angle theorem tells us ...

  • arc AD = 2∠DEA
  • arc CA = 2∠B
  • arc BA = 2∠C

Making these substitutions into the above equation, we have ...

  4∠DEA = 2∠B -2∠C

Dividing by 4 gives the relation we're trying to prove:

  ∠DEA = 1/2(∠B -∠C)