The magnitude of the resulting spring force when the material is stretched from its equilibrium position is -0.02522 N.
The spring force is a spring or a stretchy material is given by the formula,
F = -1/2Kx²
Where z
F is the spring force,
K is the spring constant,
x is the compression or extension in the material,
The negative sign represent that the force is restoring in nature.
We know, in our case,
The extension in the material is 2.71cm.
1 cm = 1/100m
So,
2.71 cm = 2.71/100m
The spring constant is 68.7N/m.
Now, putting all the values,
F = 1/2Kx²
F = -1/2(68.6)(2.71/100)²
F = -0.02522N.
So, the spring force is 0.02522N.
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