Answer :
The minimum speed necessary for the diver to clear the rocks 10.59m/s and the diver will be in air for about 2 seconds.
From the provided situation, we can analyze that the path of travel of the diver will be a projectile.
The maximum horizontal range is 35 meters.
And the height required is 5 meters.
We know, for a projectile,
Horizontal range R is given by U²sin(2A)/g
The height H attained is given by U²sin²A/2g
Dividing the height by range,
H/R = tanA/4
TanA = 20/7
Now, we can find,
SinA = 21.18
We know,
H = U²sin²A/2g
U²=2Hg/Sin²A
U²=2(5)(10)/(20/21.18)²
U = 10.59m/s.
The diver should start with speed of 10.59m/s to clear the rocks.
The time of flight is given by,
T = 2UsinA/g
Putting the values,
T = 2(10.59)(20/21.18)/10
T = 2 seconds.
The diver will be in air for 2 seconds.
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