Answer :
1.82 kgm/s and 1.82 s^-1 is momentum of the ball and of the impulse respectively applied to it by the bat.
ball mass, m = 0.145 kg
velocity of the pitched ball, v₁ = 43.5 m/s
velocity of the batted ball, v₂ = 56.0 m/s
change in the momentum is
[tex]\Delta P=mv_1-mv_2[/tex]
ΔP=6.30-8.12
ΔP=-1.82 kgm/s
The ball's change in momentum is equal to the impulse it experiences.
[tex]J=\Delta P= 1.82/s[/tex]
A moving particle's change in dynamical state can be estimated using the physical quantity known as impulse. It is the change in momentum that a body experiences when it is briefly impacted by a force. It is a vector quantity, and the letter J is used to denote it.
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