Answer :
The magnitude of the charge on the particle is 0.0083 C.
The centripetal force acting on the charged particle is equal tp the magnetic force.
[tex]\frac{mv^{2} }{r}[/tex] = qB
q = [tex]\frac{mv}{rB}[/tex]
= [tex]\frac{(0.0020kg)(5.0m/s))}{(0.20 m)(60T)}[/tex]
= 8.33 × 10⁻³ C 0r 0.0083 C
A magnetic field is a vector discipline that describes the magnetic influence on transferring electric fees, electric currents, and magnetic materials. A shifting charge in a magnetic subject experiences a pressure perpendicular to its very own pace and to the magnetic area.
This force causes the magnets to attract or repel each other. Examples of magnetic force are a compass, a motor, the magnets that maintain stuff at the fridge, educate tracks, and new roller coasters. All transferring costs deliver upward thrust to a magnetic subject and the costs that circulate via its regions, revel in pressure.
Learn more about the magnetic fields here:-https://brainly.com/question/9719792
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