when resistors 1 and 2 are connected in series, the equivalent resistance is 13.6. when they are connected in parallel, the equivalent resistance is 2.40. what are (a) the smaller resistance and (b) the larger resistance of these two resistors?



Answer :

The larger resistance is R₂ =12Ω.

Resistance values are expressed in ohms (Ω). when an electron differential exists among terminals, energy will float from excessive to low. Resistance counteracts that waft. The greater the resistance, the lower the current. Conversely, the decrease in the resistance, the extra the modern.

series connection:- R equivalent = R₁ + R₂

                                     R₁ + R₂ = 13.6 Ω

R₁ = 13.6 Ω - R₂

parallel connection:- R equival;ent =  R₁R₂ / R₁ + R₂

                                       2.40 = R₁R₂ / R₁ + R₂

2.40 = R₁R₂ / 13.6 Ω

R₁R₂ = 2.40 × 13.6 Ω

 R₁R₂ = 32.64 Ω

2.40 = R₁R₂ / R₁ + R₂

R₁ + R₂ =  32.64 Ω /  2.40 Ω

R₁ + R₂ = 13.6.

​  must be 4.0Ω and 13.6Ω, respectively.

(a) The smaller resistance is R₁ =4.0Ω

(b) The larger resistance is R₂ =12Ω

An electric-powered cutting-edge flows when electrons flow through a conductor, consisting of a metallic cord. The moving electrons can collide with the ions in the steel. This makes it greater tough for the present day to flow, and reasons for resistance.

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