As a result of the law of conservation of momentum, the man will acquire a speed of 3 . 10⁻³ m/s
The law of conservation of momentum states thta:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where:
u₁ , u₂ = initial velocity of object 1 and object 2
v₁ , v₂ = final velocity of object 1 and object 2
Since both the man and the shove are initially at rest, hence u₁ , u₂ = 0.
Therefore,
m₁v₁ + m₂v₂ = 0
Parameters given:
m₁ = 95 kg
m₂ = 74 gram = 74 . 10⁻³ kg
v₂ = 4 m/s
Plug these parameters into the equation:
95 . v₁ + 74 . 10⁻³ . 4 = 0
v₁ = 3 . 10⁻³ m/s
Hence, the man acquire a speed of 3 . 10⁻³ m/s, which is very small.
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