Answer :
The salesman used 460 order forms in total, when he used three types of order forms: a, b, c.
Given that,
A salesman used three types of order forms: a, b, c. he used 50 of form a. of form b he used four times as many as form a plus 1/2 as many as form c. he used as many of form c as form a plus 1/2 as many as form b
A = 50
B = 4A + 0.5C = 200+ 0.5C .......... (i)
C = A + 0.5B = 50 + 0.5 B .......... (ii)
multiply (ii) with 2
B = 2C -50 .......... (iii)
B = 0.5C + 160 ...........(i)
subtract (i) from (iii)
0 = 1.5C -210
C = 420/3 = 140
put in (i)
B = 200 + 0.5(140) = 270
Total forms = A+B+C = 50 + 270 + 140 = 460
Therefore, he used 460 forms altogether.
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