145-g baseball is dropped from a tree 12.0 m above the ground. (a) with what speed would it hit the ground if air resistance could be ignored? (b) if it actually hits the ground with a speed of what is the average force of air resistance exerted on it?



Answer :

The required speed is 15.35 m/s, if air resistance is ignored.

The magnitude of average force of air resistance is 1.0341N.

a) V = √2gh

The required speed is

V = √2(9.8)(12)

V = 15.35m/s

b) W = 1/2m([tex]v^{2}[/tex]-[tex]u^{2}[/tex])

    W = (mg - f)h

 ( (0.145)(9.8) - f)12 = 1/2(0.145)(([tex]8^{2}[/tex]))

(1.421 - f)12 = 4.64

Force of an air resistance  = 1.0341N

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