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a square loop of wire with initial side length 20 cm is placed in a magnetic field of strength 0.5 t. the field is parallel to the axis of the loop. somebody carefully grabs the edges of the loop and begins pulling them apart such that the area of the loop increases at a rate of 20 cm2/s. what is the magnitude of the induced emf in the loop?



Answer :

The magnitude of the induced emf in the loop is 1mV.

The formula to be used is:

E = B (dA/dt)

B = magnetic of magnetic field parallel to the axis of loop = 0.5 T

dA/dt = rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²

θ = Angle of the magnetic field with the area vector = 0

E = emf induced in the loop

Now, plugging in the values we get:

E = B (dA/dt)

E = (0.5) (20 x 10⁻⁴ )

E = 10 x [tex]10^{-4}[/tex] volts

E = 1 mV

Therefore,  the magnitude of the induced emf in the loop is 1mV.

Learn more about emf induced in the loop here:

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