an elevator of mass m is initially at rest on the first floor of a building. it moves upward, and passes the second and third floors with a constant velocity, and finally stops at the fourth floor. the distance between adjacent floors is h. what is the net work done on the elevator during the entire trip, from the first floor to the fourth floor?

Question

21-10-2022
Physics

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an elevator of mass m is initially at rest on the first floor of a building. it moves upward, and passes the second and third floors with a constant velocity, and finally stops at the fourth floor. the distance between adjacent floors is h. what is the net work done on the elevator during the entire trip, from the first floor to the fourth floor?

Answer :

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fawadmohd fawadmohd · Answer 1 · 2022-10-25T02:50:55-04:00

From the first floor to the fourth floor, the elevator's net work during the entire trip is -3mgh.

Given,

On the first floor of a building, an elevator with mass m is initially at rest. It ascends at a constant speed, passing second and third floors before coming to a stop at the fourth floor.

the separation between the floors is h

The distance from the first floor to the fourth floor Equals 3 hours of work = -mg(3 hours)

= -3mgh

Work Done = -3mgh

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