a swan on a lake gets airborne by flapping its wings and running on top of the water. (a) if the swan must reach a velocity of 5.80 m/s to take off and it accelerates from rest at an average rate of 0.305 m/s2, how far (in m) will it travel before becoming airborne?

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21-10-2022
Physics

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a swan on a lake gets airborne by flapping its wings and running on top of the water. (a) if the swan must reach a velocity of 5.80 m/s to take off and it accelerates from rest at an average rate of 0.305 m/s2, how far (in m) will it travel before becoming airborne?

Answer :

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aditmarkas98 aditmarkas98 · Answer 1 · 2022-10-25T05:52:03-04:00

The swan will travel 55.15 m during uniform motion before becoming airbone.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 0 m/s

vt = 5.8 m/s

a = 0.305 m/s²

By using the second equation, we can calculate the distance before becoming airbone

vt² = vo² + 2a . s

5.8² = 0² + 2 . 0.305 . s

0.61s = 33.64

s = 55.15 m

Find more on uniform motion at: https://brainly.com/question/28040370

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