a propeller is modeled as five identical uniform rods extending radially from its axis. the length and mass of each rod are 0.711 m and 2.99 kg, respectively. when the propellor rotates at 569 rpm (revolutions per minute), what is its rotational kinetic energy?

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21-10-2022
Physics

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a propeller is modeled as five identical uniform rods extending radially from its axis. the length and mass of each rod are 0.711 m and 2.99 kg, respectively. when the propellor rotates at 569 rpm (revolutions per minute), what is its rotational kinetic energy?

Answer :

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aditmarkas98 aditmarkas98 · Answer 1 · 2022-10-25T06:33:40-04:00

The rotational kinetic energy of five identical uniform rods is 9436.21 joule.

We need to know about rotational kinetic energy to solve this problem. Rotational kinetic energy can be defined as the energy of a rotating object. The magnitude of rotational energy is

KE = 1/2 . I . ώ²

where KE is rotational kinetic energy, I is inertia and ώ is angular velocity.

From the question above, the given parameters are

L = 0.711 m

m = 2.99 kg

N = 5

ώ = 569 rpm = 59.59 rad/s

Find the total inertia of five identical rods

I = N . 1/2 . m . L²

I = 5 . 1/2 . 2.99 . 0.711

I = 5.31 kg.m²

Calculate the rotational kinetic energy

KE = 1/2 . I . ώ²

KE = 1/2 . 5.31 . 59.59²

KE = 9436.21 joule

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