eamonn has just taken a statistics exam, and he wants to calculate a confidence interval to represent the exam scores in his class. the test mean was 75, with a standard deviation of 5. there are 30 students in the class. the 90% confidence interval for the class is:



Answer :

The 90% confidence interval for the class is [73.49, 76.51].

Confidence interval is defined as the range of values where a parameter might fall at a given confidence level. It can be calculated using the formula below.

CI = μ ± z x SD/√n

where CI = confidence interval

μ = sample mean = 75

z = found by using a z-score table

SD = sample standard deviation = 5

n = sample size = 30

At 90% confidence level, the area in each tail of the standard normal curve is 5, and the cumulative area up to the second tail is 95.

(100 - 90) / 2 = 5

100 - 5 = 95

Find 0.95 in the z-table to get the value of z.

At p = 0.95, z = 1.65

Plug in the values to the formula for confidence interval, CI.

CI = μ ± z x SD/√n

CI = 75 ± 1.65 x 5/√30

CI = 75 ± 1.51

CI = [73.49, 76.51]

Hence, for every 100 samples, at 90% confidence level, the mean will be between 73.49 and 76.51.

Learn more about confidence of interval here: https://brainly.com/question/15905481

#SPJ4

View image jcmacahia7
View image jcmacahia7

Other Questions